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Proof step 3 from proof isSquare-10pot (previous step)

⊦ ∃ j. j * j = 10 ^ (2 * abs(i))

User applied rule exists right

And obtained the following new goals

Proof step 4:
⊦ 10 ^ abs(i) * 10 ^ abs(i) = 10 ^ (2 * abs(i))

Rule argument

pos: right 1 terms: 10 ^ abs(i) abort: F discard: T computed: F

Additional information

Used terms: 10 ^ abs(i)