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Proof step 7 from proof one-01 (
previous step
)
j < 0, j ≤ 0 ⊦ 1 / 1 ^ abs(j) = 1
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 8
:
⊦ j < 0 → abs(j) = 0 - j
Proof step 9
:
j < 0, j < 0, j ≤ 0 ⊦ 1 / 1 ^ (0 - j) = 1
Rule argument
spec: int-abs inst: name: Abs-neg seq: ⊦ j < 0 → abs(j) = 0 - j subst: [j] → [j] flags: rewrite
Additional information
Used terms: j