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Proof step 9 from proof one-01 (previous step)

j < 0, j < 0, j ≤ 0 ⊦ 1 / 1 ^ (0 - j) = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
j < 0, j ≤ 0 ⊦ 1 ^ ~ j = 1

Rule argument

Additional information

Used simplifier rules: zero-02: ⊦ j < 0 → (i ^ ~ j = 0 ↔ i = 0);%one-02: j ≠ 0 ⊦ 1 / j = 1 ↔ j = 1; from specification int-div%neg-06: ⊦ 0 - i = ~ i; from specification int-abs