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Proof step 4 from proof pot-mod-add-zero (previous step)

0 < j0, 0 ≤ j, 0 < j0 ⊦ (i + i0 * j ^ j0 -1 * j) % j = 0 ↔ i % j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 ≤ j, 0 < j0 ⊦ (i + i0 * j ^ (j0 - 1) * j) % j = 0 ↔ i % j = 0

Rule argument

Additional information

Used simplifier rules: associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%sub-pred: ⊦ i -1 = i - 1; from specification int-abs