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Proof step 5 from proof pot-mod-add-zero (previous step)

0 ≤ j, 0 < j0 ⊦ (i + i0 * j ^ (j0 - 1) * j) % j = 0 ↔ i % j = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 6:
j0 = i1 + 1, 0 ≤ j, 0 < j0 ⊦ (i + i0 * j ^ i1 * j) % j = 0 ↔ i % j = 0

Rule argument

spec: int-abs inst: name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [j0, 1, i1] flags:

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: j0, 1, i1