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Proof step 15 from proof square-le-one (previous step)

1 < (sqrt(i) + 1)^2, 0 < (sqrt(i) + 1)^2, sqrt(i) ^2 < (sqrt(i) + 1)^2, 4 < (sqrt(i) + 1)^2, i < (sqrt(i) + 1)^2, sqrt(i) ^2 ≤ i, 0 ≤ i, 4 ≤ i, sqrt(i) ≤ 1, 0 < i, sqrt(i) < (sqrt(i) + 1)^2 ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 16:
4 = 2 ^2, 1 < (sqrt(i) + 1)^2, 0 < (sqrt(i) + 1)^2, sqrt(i) ^2 < (sqrt(i) + 1)^2, 4 < (sqrt(i) + 1)^2, i < (sqrt(i) + 1)^2, sqrt(i) ^2 ≤ i, 0 ≤ i, 4 ≤ i, sqrt(i) ≤ 1, 0 < i, sqrt(i) < (sqrt(i) + 1)^2 ⊦
Proof step 19:
1 < (sqrt(i) + 1)^2, 0 < (sqrt(i) + 1)^2, sqrt(i) ^2 < (sqrt(i) + 1)^2, 4 < (sqrt(i) + 1)^2, i < (sqrt(i) + 1)^2, sqrt(i) ^2 ≤ i, 0 ≤ i, 4 ≤ i, sqrt(i) ≤ 1, 0 < i, sqrt(i) < (sqrt(i) + 1)^2 ⊦ 4 = 2 ^2

Rule argument

fma: 4 = 2 ^2

Additional information

Used formulas: 4 = 2 ^2