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Proof step 19 from proof square-le-one (
previous step
)
1 < (sqrt(i) + 1)^2, 0 < (sqrt(i) + 1)^2, sqrt(i) ^2 < (sqrt(i) + 1)^2, 4 < (sqrt(i) + 1)^2, i < (sqrt(i) + 1)^2, sqrt(i) ^2 ≤ i, 0 ≤ i, 4 ≤ i, sqrt(i) ≤ 1, 0 < i, sqrt(i) < (sqrt(i) + 1)^2 ⊦ 4 = 2 ^2
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 20
:
⊦ i ^2 = i * i
Rule argument
spec: inst: name: Square-def seq: ⊦ i ^2 = i * i subst: [i] → [2] flags: rewrite, current
Additional information
Used terms: 2