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Proof step 1 from proof square-not-neg-02 (conclusion)

⊦ 0 ≤ i → (sqrt(i) ≤ 0 ↔ i = 0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
sqrt(i) ≤ 0, sqrt(i) < i, 0 < i ⊦ i = 0

Rule argument

Additional information

Used simplifier rules: zero-01: ⊦ sqrt(0) = 0;%forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%lels-02: ⊦ i ≠ j → (i ≤ j ↔ i < j); from specification int-abs