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Proof step 2 from proof square-not-neg-02 (previous step)

sqrt(i) ≤ 0, sqrt(i) < i, 0 < i ⊦ i = 0

User applied rule insert lemma

And obtained the following new goals

Rule argument

spec: inst: name: root-pos seq: ⊦ 0 ≤ i → 0 ≤ sqrt(i) subst: [i] → [i] flags: current, []

Additional information

Used simplifier rules: square-not-neg-05: ⊦ 0 < i → sqrt(i) ≠ 0;%lels-02: ⊦ i ≠ j → (i ≤ j ↔ i < j); from specification int-abs%anti: ⊦ i ≤ j → (j ≤ i ↔ i = j); from specification int-abs Used terms: i