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Proof step 1 from proof first-num (conclusion)
n ≠ 0 ⊦ firstn((* n), x) = x.first ' + firstn(n -1, x.rest)
Special step normalize
And obtained the following new goals
Proof step 2
:
n ≠ 0 ⊦ firstn(n, x) = x.first ' + firstn(n -1, x.rest)