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Proof step 2 from proof first-num (previous step)

n ≠ 0 ⊦ firstn(n, x) = x.first ' + firstn(n -1, x.rest)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ n = 0, firstn(n, x) = x.first ' + firstn(n - 1, x.rest)

Rule argument

Additional information

Used simplifier rules: pred-03: ⊦ n -1 = n - 1; from specification nat