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Proof step 2 from proof firstn-first (previous step)

⊦ firstn(n, x).first = x.first, x = [], n = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
x = a + y ⊦ firstn(n, x).first = a, x = [], n = 0

Rule argument

spec: list-data inst: name: elim-list-c seq: x ≠ [] ⊦ a = x.first ∧ y = x.rest ↔ x = a + y subst: [x, a, y] → [x, a, y] flags:

Additional information

Used simplifier rules: x ≠ [] ⊦ a = x.first ∧ y = x.rest ↔ x = a + y; (elim) Used terms: x, a, y