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Proof step 3 from proof firstn-first (previous step)

x = a + y ⊦ firstn(n, x).first = a, x = [], n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ n = 0, firstn(n, a ' + y).first = a

Rule argument

Additional information

Used simplifier rules: a: ⊦ (x + y) + z = x + y + z; from specification list%e-01: ⊦ a ' + x ≠ []; from specification list%c: ⊦ a + x = a ' + x; from specification list