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Proof step 1 from proof lastN-in (conclusion)

⊦ ¬ a ∈ x ∧ n < # x → ¬ a ∈ lastn(n, x)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n < # x, a ∈ lastn(n, x) ⊦ x = [], a ∈ x

Rule argument

Additional information

Used simplifier rules: l: ⊦ # x = 0 ↔ x = []; from specification list-data%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1