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Proof step 2 from proof lastN-in (previous step)

n < # x, a ∈ lastn(n, x) ⊦ x = [], a ∈ x

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ ¬ a ∈ x ∧ n ≤ # x → ¬ a ∈ lastn(n, x)

Rule argument

spec: list-del inst: name: lastN-in-01 seq: ⊦ ¬ a ∈ x ∧ n ≤ # x → ¬ a ∈ lastn(n, x) subst: [x, n, a] → [x, n, a] flags: rewrite, current

Additional information

Used simplifier rules: lels-03: ⊦ m < n → m ≤ n; from specification nat Used terms: x, n, a