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Proof step 2 from proof rest-app (previous step)

# x ≤ m, m ≤ # x + # y ⊦ restn(m, x + y) = restn(m - # x, y)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
m = n0 + # x, # x ≤ m, m ≤ # x + # y ⊦ restn(m, x + y) = restn(n0, y)

Rule argument

spec: nat inst: name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [m, # x, n] flags:

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: m, # x, n