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Proof step 3 from proof rest-app (previous step)

m = n0 + # x, # x ≤ m, m ≤ # x + # y ⊦ restn(m, x + y) = restn(n0, y)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
n0 ≤ # y ⊦ restn(n0 + # x, x + y) = restn(n0, y)

Rule argument

Additional information

Used simplifier rules: lep-02: ⊦ m + n ≤ m + n0 ↔ n ≤ n0; from specification nat%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%lep: ⊦ m ≤ m + n; from specification nat