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Proof step 10 from proof perm-del-01 (previous step)

perm(x -l a, z), perm(x, y), perm(z, x -l a), ∀ a. a ∈ y ∨ a ∈ x → #oc(a, y) = #oc(a, x), a0 ∈ y -l a ∨ a0 ∈ z ⊦ #oc(a0, y) = #oc(a0, z), a0 = a

User applied rule all left

And obtained the following new goals

Proof step 11:
perm(x -l a, z), perm(x, y), perm(z, x -l a), a0 ∈ y ∨ a0 ∈ x → #oc(a0, y) = #oc(a0, x), a0 ∈ y -l a ∨ a0 ∈ z ⊦ #oc(a0, y) = #oc(a0, z), a0 = a

Rule argument

pos: left 4 terms: a0 abort: F discard: T computed: T

Additional information

Used terms: a0