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Proof step 11 from proof perm-del-01 (previous step)

perm(x -l a, z), perm(x, y), perm(z, x -l a), a0 ∈ y ∨ a0 ∈ x → #oc(a0, y) = #oc(a0, x), a0 ∈ y -l a ∨ a0 ∈ z ⊦ #oc(a0, y) = #oc(a0, z), a0 = a

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 12:
⊦ a ∈ x -l b ↔ a ∈ x ∧ a ≠ b
Proof step 13:
perm(x -l a, z), perm(x, y), perm(z, x -l a), a0 ∈ y ∨ a0 ∈ x → #oc(a0, y) = #oc(a0, x), a0 ∈ y ∧ a0 ≠ a ∨ a0 ∈ z ⊦ #oc(a0, y) = #oc(a0, z), a0 = a

Rule argument

spec: list-del inst: name: in-del-new seq: ⊦ a ∈ x -l b ↔ a ∈ x ∧ a ≠ b subst: [b, x, a] → [a, y, a0] flags: rewrite

Additional information

Used terms: a, y, a0