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Proof step 10 from proof subrec (previous step)

∀ a0. #oc(a0, a ') + #oc(a0, x) ≤ #oc(a0, y) ⊦ a ∈ y ∧ #oc(a0, x) ≤ #oc(a0, y -1l a)

Heuristic pl case distinction applied rule case distinction

And obtained the following new goals

Proof step 11:
∀ a0. #oc(a0, a ') + #oc(a0, x) ≤ #oc(a0, y) ⊦ a ∈ y
Proof step 12:
∀ a0. #oc(a0, a ') + #oc(a0, x) ≤ #oc(a0, y) ⊦ #oc(a0, x) ≤ #oc(a0, y -1l a)

Rule argument

pos: right 1

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