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Proof step 9 from proof subrec (previous step)

∀ a0. #oc(a0, a ') + #oc(a0, x) ≤ #oc(a0, y) ⊦ a ∈ y ∧ (∀ a0. #oc(a0, x) ≤ #oc(a0, y -1l a))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
∀ a0. #oc(a0, a ') + #oc(a0, x) ≤ #oc(a0, y) ⊦ a ∈ y ∧ #oc(a0, x) ≤ #oc(a0, y -1l a)

Rule argument

Additional information