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Proof step 2 from proof diff-wfrec (previous step)

⊦ x \ (a ' + y) = (x -l a) \ y

User applied rule structural induction

And obtained the following new goals

Proof step 3:
∀ a, y. x0 \ (a ' + y) = (x0 -l a) \ y ⊦ (a0 + x0) \ (a ' + y) = ((a0 + x0) -l a) \ y

Rule argument

indvar: x

Additional information

Used simplifier rules: diff-e: ⊦ [] \ y = [];%list freely generated by [], +;;%del-e: ⊦ [] -l a = []; from specification list-del