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Proof step 3 from proof diff-wfrec (previous step)

∀ a, y. x0 \ (a ' + y) = (x0 -l a) \ y ⊦ (a0 + x0) \ (a ' + y) = ((a0 + x0) -l a) \ y

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
∀ a, y. x0 \ (a ' + y) = (x0 -l a) \ y ⊦ (a0 ' + x0) \ (a ' + y) = ((a0 ' + x0) -l a) \ y

Rule argument

Additional information

Used simplifier rules: c: ⊦ a + x = a ' + x; from specification list