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Proof step 1 from proof size-le (conclusion)

⊦ #(x ∪ y) ≤ # rmdup(y) ↔ x ⊆ y

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ # rmdup(x + y) ≤ # rmdup(y) ↔ x ⊆ y

Rule argument

Additional information

Used simplifier rules: union: ⊦ x ∪ y = rmdup(x + y);%assoc: ⊦ (x ∪ y) ∪ z = x ∪ y ∪ z;