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Proof step 2 from proof size-le (previous step)

⊦ # rmdup(x + y) ≤ # rmdup(y) ↔ x ⊆ y

User applied rule case distinction

And obtained the following new goals

Proof step 3:
# rmdup(x + y) ≤ # rmdup(y) ⊦ x ⊆ y
Proof step 6:
x ⊆ y ⊦ # rmdup(x + y) ≤ # rmdup(y)

Rule argument

pos: right 1

Additional information