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Proof step 18 from proof nu-is-UN (previous step)

∀ x. compl(f)(S)(x) → S(x) ⊦ S(x), f(λ x0. ¬ S(x0))(x0), S(x0)

User applied rule all left

And obtained the following new goals

Proof step 19:
compl(f)(S)(x0) → S(x0) ⊦ S(x), f(λ x0. ¬ S(x0))(x0), S(x0)

Rule argument

pos: left 1 terms: x0 abort: F discard: T computed: T

Additional information

Used terms: x0