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Proof step 19 from proof nu-is-UN (previous step)

compl(f)(S)(x0) → S(x0) ⊦ S(x), f(λ x0. ¬ S(x0))(x0), S(x0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
⊦ S(x), f(λ x0. ¬ S(x0))(x0), S(x0), compl(f)(S)(x0)

Rule argument

Additional information