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Proof step 20 from proof nu-is-UN (
previous step
)
⊦ S(x), f(λ x0. ¬ S(x0))(x0), S(x0), compl(f)(S)(x0)
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 21
:
⊦ compl(f)(S)(x) ↔ ¬ f(λ x0. ¬ S(x0))(x)
Rule argument
spec: inst: name: compl-def seq: ⊦ compl(f)(S)(x) ↔ ¬ f(λ x0. ¬ S(x0))(x) subst: [x, S, f] → [x0, S, f] flags: rewrite, current
Additional information
Used terms: x0, S, f