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Proof step 2 from proof even-05 (previous step)

m + m = (m0 + m0) + n, m < m0 ⊦ m0 = 0

User applied rule cut formula

And obtained the following new goals

Proof step 3:
m + m < m0 + m0, m + m = (m0 + m0) + n, m < m0 ⊦ m0 = 0

Rule argument

fma: m + m < m0 + m0

Additional information

Used simplifier rules: l-03: ⊦ m < m0 ∧ n < n0 → (¬ m + n < m0 + n0 ↔ false);%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m; Used formulas: m + m < m0 + m0