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Proof step 3 from proof even-05 (previous step)

m + m < m0 + m0, m + m = (m0 + m0) + n, m < m0 ⊦ m0 = 0

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 2 flags: discard

Additional information

Used simplifier rules: l: ⊦ m + n < m + n0 ↔ n < n0;%l-02: ⊦ ¬ m + n < m;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;