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Proof step 2 from proof ex-oddeven (previous step)

⊦ ∃ m. m + m = 0 ∨ m + m + 1 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ ∃ m. m + m = 0

Rule argument

Additional information

Used simplifier rules: oz: ⊦ m + 1 ≠ 0;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;