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Proof step 1 from proof ex-oddeven (conclusion)

⊦ ∃ m. m + m = n ∨ m + m + 1 = n

User applied rule structural induction

And obtained the following new goals

Proof step 2:
⊦ ∃ m. m + m = 0 ∨ m + m + 1 = 0
Proof step 4:
∃ m. m + m = n0 ∨ m + m + 1 = n0 ⊦ ∃ m. m + m = n0 +1 ∨ m + m + 1 = n0 +1

Rule argument

indvar: n

Additional information

Used simplifier rules: nat freely generated by 0, +1;;