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Proof step 4 from proof ex-oddeven (previous step)

∃ m. m + m = n0 ∨ m + m + 1 = n0 ⊦ ∃ m. m + m = n0 +1 ∨ m + m + 1 = n0 +1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
m + m = n0 ∨ m + m + 1 = n0 ⊦ ∃ m0. m0 + m0 = n0 + 1 ∨ m0 + m0 = n0

Rule argument

Additional information

Used simplifier rules: succ: ⊦ m +1 = m + 1;%eq-01: ⊦ m + n = m + n0 ↔ n = n0;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;