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Proof step 3 from proof l-05 (previous step)

∀ m, n, n0. ¬(m + m1 < n ∧ n + n0 < m), m + m1 +1 < n, n + n0 < m ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
n + n0 < m, m + m1 + 1 < n, ∀ m0, n1, n2. ¬ m0 + m1 < n1 ∨ ¬ n1 + n2 < m0 ⊦

Rule argument

Additional information

Used simplifier rules: succ: ⊦ m +1 = m + 1;