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Proof step 4 from proof l-05 (previous step)

n + n0 < m, m + m1 + 1 < n, ∀ m0, n1, n2. ¬ m0 + m1 < n1 ∨ ¬ n1 + n2 < m0 ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: m, n, n0

Additional information

Used simplifier rules: nls-snd: ⊦ ¬ m0 < n → ¬ m + m0 < n;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m; Used terms: m, n, n0