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Proof step 10 from proof three (previous step)

3 = 1 + 2, 1 + m = 3 ⊦ m = 1, m = 0, m = 2

User applied rule insert equation

And obtained the following new goals

Proof step 11:
1 + m = 1 + 2 ⊦ m = 1, m = 0, m = 2

Rule argument

pos: left 1 flags: discard

Additional information