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Proof step 9 from proof three (previous step)

1 + m = 3 ⊦ m = 1, m = 0, m = 2

User applied rule cut formula

And obtained the following new goals

Proof step 10:
3 = 1 + 2, 1 + m = 3 ⊦ m = 1, m = 0, m = 2

Rule argument

fma: 3 = 1 + 2

Additional information

Used simplifier rules: a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m; Used formulas: 3 = 1 + 2