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Proof step 3 from proof two-02 (previous step)

m0 + m0 + m0 ≠ 2, m0 +1 + m0 +1 + m0 +1 = 2 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
3 + m0 + m0 + m0 = 2 ⊦ m0 + m0 + m0 = 2

Rule argument

Additional information

Used simplifier rules: succ: ⊦ m +1 = m + 1;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;