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Proof step 4 from proof two-02 (previous step)

3 + m0 + m0 + m0 = 2 ⊦ m0 + m0 + m0 = 2

User applied rule cut formula

And obtained the following new goals

Proof step 5:
3 = 2 + 1, 3 + m0 + m0 + m0 = 2 ⊦ m0 + m0 + m0 = 2

Rule argument

fma: 3 = 2 + 1

Additional information

Used simplifier rules: a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m; Used formulas: 3 = 2 + 1