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Proof step 12 from proof even-mult (previous step)

2 * m0 = n * 2 * m1 + n ⊦ ∃ m0. 2 * m0 = n

User applied rule exists right

And obtained the following new goals

Rule argument

pos: right 1 terms: m0 - n * m1 abort: F discard: T computed: F

Additional information

Used terms: m0 - n * m1