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Proof step 11 from proof even-mult (previous step)

2 * m0 = m * n ⊦ ∀ m0. m ≠ m0 + m0 + 1, ∃ m0. 2 * m0 = m, ∃ m0. 2 * m0 = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: two-succ-05: ⊦ 2 * m ≠ 2 * n + 1; from specification nat-mult%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%rsucc-02: ⊦ m * (n + 1) = m * n + m; from specification nat-mult%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%two-02: ⊦ m + m = 2 * m; from specification nat-mult