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Proof step 9 from proof even-mult (previous step)

2 * m0 = m * n ⊦ ¬ odd(m), ∃ m0. 2 * m0 = m, ∃ m0. 2 * m0 = n

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ odd(n) ↔ (∃ m. n = m + m + 1)
Proof step 11:
2 * m0 = m * n ⊦ ∀ m0. m ≠ m0 + m0 + 1, ∃ m0. 2 * m0 = m, ∃ m0. 2 * m0 = n

Rule argument

spec: inst: name: oex seq: ⊦ odd(n) ↔ (∃ m. n = m + m + 1) subst: [n] → [m] flags: rewrite, current

Additional information

Used terms: m