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Proof step 5 from proof even-mult (previous step)

even(m), 2 * m0 = m * n ⊦ ∃ m0. 2 * m0 = m, ∃ m0. 2 * m0 = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
2 * m0 = (2 * m1) * n ⊦ ∃ m0. 2 * m0 = n, ∃ m0. 2 * m0 = 2 * m1

Rule argument

Additional information

Used simplifier rules: Even: ⊦ even(n) ↔ (∃ m. m + m = n);%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%two-02: ⊦ m + m = 2 * m; from specification nat-mult