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Proof step 6 from proof even-mult (previous step)

2 * m0 = (2 * m1) * n ⊦ ∃ m0. 2 * m0 = n, ∃ m0. 2 * m0 = 2 * m1

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: m1

Additional information

Used terms: m1