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Proof step 1 from proof max-a (conclusion)

⊦ max(m, max(n, n0)) = max(max(m, n), n0)

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 2:
m < max(n, n0) ⊦ max(m, max(n, n0)) = max(max(m, n), n0)
Proof step 8:
⊦ m < max(n, n0), max(m, max(n, n0)) = max(max(m, n), n0)

Rule argument

fma: m < max(n, n0)

Additional information

Used formulas: m < max(n, n0)