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Proof step 8 from proof max-a (previous step)

⊦ m < max(n, n0), max(m, max(n, n0)) = max(max(m, n), n0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
max(n, n0) ≤ m ⊦ m = max(max(m, n), n0)

Rule argument

Additional information

Used simplifier rules: Max-right: ⊦ ¬ m < n → max(m, n) = m;%lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat