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Proof step 9 from proof max-a (previous step)

max(n, n0) ≤ m ⊦ m = max(max(m, n), n0)

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 10:
n < n0, max(n, n0) ≤ m ⊦ m = max(max(m, n), n0)
Proof step 16:
max(n, n0) ≤ m ⊦ n < n0, m = max(max(m, n), n0)

Rule argument

fma: n < n0

Additional information

Used formulas: n < n0