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Proof step 8 from proof min-a (previous step)

min(m, n) < n0, n < n0, n ≤ m ⊦ n = min(min(m, n), n0), n0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
min(m, n) < n0, n < n0, n ≤ m ⊦ n0 = 0, n = min(m, n)

Rule argument

Additional information

Used simplifier rules: Min-left: ⊦ m < n → min(m, n) = m;