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Proof step 9 from proof min-a (previous step)

min(m, n) < n0, n < n0, n ≤ m ⊦ n0 = 0, n = min(m, n)

Heuristic weak cut applied rule cut formula

And closed the goal!

Rule argument

fma: m < n

Additional information

Used simplifier rules: Min-left: ⊦ m < n → min(m, n) = m;%Min-right: ⊦ ¬ m < n → min(m, n) = n;%le-ls-simp: ⊦ m ≤ n → (n < m ↔ false); from specification nat Used formulas: m < n