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Proof step 10 from proof odd-mult (previous step)

2 * m0 = m * n ⊦ ∃ m0. 2 * m0 = n, ∃ m0. 2 * m0 = m

User applied rule exists right

And obtained the following new goals

Proof step 11:
2 * m0 = m * n ⊦ 2 * n / 2 = n, ∃ m0. 2 * m0 = m

Rule argument

pos: right 1 terms: n / 2 abort: F discard: T computed: F

Additional information

Used terms: n / 2